Half life of first order reaction is 20 min ,How many grams of reactant will be left behind after an hour if we started with 80 grams of reactant 1 point A. 20 g B. 10 g C. 5 g D. 36g Answer with explanation
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Answer:
t= k2.303
log( a−xa)
t= 10 −2/s2.303
log( 5g20g)
t=138.6 sec
Hence, the time required will be 138.6 sec.
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