Physics, asked by ashutosh3833, 1 year ago

five led bulbs of 8 w each ,two fans of 40w each , an electric motor of 3 kw ,and a geyser of 5 kw are used for 8 hours per day by a family. calculate the total energy consumed in 30 days and the cost of electricity used in one day at rate of rs 5 per unit​

Answers

Answered by SreenikethanI
143

Usage of all Electric bulbs = 8W \times 5 = 40W

Usage of all Electric fans = 40W \times 2 = 80W

Usage of Electric motor = 3kW = 3000W

Usage of Electric geyser = 5kW = 5000W

Total Power usage = 40 + 80 + 3000 + 5000 = 8120W

Total Power usage in kW =\frac{8120}{1000}

=8.12 kW

Total time = 8 hours

∴ Total Energy used = kW \times hours

=8.12 \times 8

=64.96 kWh

Rate per kWh = ₹5

∴ Total cost for one day = Rate \times kWh

= 5 \times 64.96

= 324.8

Number of days = 30 days

∴ Total cost for 30 days = cost of one day \times no. of days

= 324.8 \times 30

= 9744

The electricity bill for 30 days is ₹9744.

Please mark this as Brainliest if this was helpful!

Answered by tanisa2105
33

Answer:

Hope you have understand mate

The electricity bill that will come, it will show Rs. 9744

*lol, in this method we can also calculate our own electricity bill. that would be fun :) JK

Anyway will surely love to help more in the future

BYE BYE....

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