Five years ago a man by 7 time oldest his son.After 5 year he will be twice oldest son. Find their present age.
Answers
Let us Assume That, Present age of man and his eldest son is x & y years.
Than,
Case ❶ :- (5 Years Ago.)
→ Father was = (x - 5) years old.
→ son was = (y - 5) years old.
A/q,
→ Father = 7 * son
→ (x - 5) = 7(y - 5)
→ x - 5 = 7y - 35
→ x - 7y = - 35 + 5
→ x - 7y = (-30) ---------- Eqn(1).
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Case ❷ :- (After 5 Years.)
→ Father will be = (x + 5) years old.
→ son will be = (y + 5) years old.
A/q,
→ Father = 2 * son
→ (x + 5) = 2(y + 5)
→ x + 5 = 2y + 10
→ x - 2y = 10 - 5
→ x - 2y = 5 ---------- Eqn(2).
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Subtracting Eqn.(2) from Eqn.(1) ,
→ (x - 7y) - (x - 2y) = (-30) - (5)
→ x - x - 7y + 2y = (-35)
→ (-5y) = (-35)
→ y = 7 .
Putting in Eqn.(1) Now,
→ x - 7*7 = (-30)
→ x - 49 = (-30)
→ x = (-30) + 49
→ x = 19.
Hence, Father Present age is 19 Years & his Eldest son Present age is 7 Years.
- Five years ago a man 7 times oldest by his son.
- After five years he will be twice the oldest son.
- Their present age
✧Let the age of man be x
✧and his son be y
☞Five years ago,
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☞After Five years ,
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According to the ques ,