Question

five years ago A man was 7 times as old as his son 5 years hence the father will be 3 times as old as his son find their present ages

Answer 1

Let the present ages of the man and his son X and Y
5 yrs ago
X - 5 = 7(Y-5)
X - 7Y = - 30
5 yrs hence
X+5 = 3(Y+5)
X - 3Y = 10
Solve the equations we get
Y = 10 yrs
And X = 40 yrs