Question

Five years ago lucky was three times as old as lovely.10 years later lucky would be twice as old as lovely.How old are they now?

Answer 1

let lucky's age be x and lovely's age be y.
lucky's age 5 years ago (x -5)
lovely's age 5 years ago (y -5)

ATQ,
X -5 = 3(Y-5)
X- 5 = 3Y -15
X-3Y= -15+5
X-3Y = -10 --------(1)

case 2
lucky's age 10 years later = ( x+10)
lovely's age 10 years later = ( y + 10)

ATQ,
X+ 10 = 2(Y+10)
X+10 = 2Y + 20
X - 2Y = 20 - 10
X - 2Y = 10 --------(2)


ELIMINATING TWO EQUATIONS,

X-3Y = -10
X-2Y = 10
-----------------
- + -

-Y = -20
Y = 20


PUTTING VALUE OF Y IN EQ (1)

X - 3(20) = -10
X -60 = -10
X = -10 + 60
X = 50


HERE IS THE ANSWER.
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