Question

Five years ago,nuri was thrice as old as sonu.Ten years later,nuri will be twic old as sonu . How old are nuri and sonu?

Answer 1

Let the age of nuri be x

Let the age of sonu be y

Five years ago:

Nuri's age = X-5

Sonu's age = Y-5

so,by condition

== (X-5) = 3(Y-5)

== X=3Y-15 + 5

== X= 3Y- 10 ...(1)

Ten years after:

Nuri's age = X+10

Sonu's age = Y+10

(X+10) = 2(Y+10)

X= 2Y+ 20 -10

X = 2Y+10

From eqution(i) X= 3Y- 10

3Y- 10 = 2Y+10

3Y- 2Y = 20

Y = 20

putting value of y in (equation 1)

→ X= 3(20)- 10

→ X= 50....

so sonu age is 20 years and nuris age is 50 years

Answer 2

$\bold{\huge{Hay!!}}$

$\bold{Dear\:user!!}$

$\bold{\underline{Question-}}$

Five years ago,nuri was thrice as old as sonu.Ten years later,nuri will be twic old as sonu . How old are nuri and sonu?

$\bold{\underline{Answer-}}$

According to the question we know that Five years ago Nuri was thrice as old as sonu.Ten years later,Nuri will be twice as old as Sonu 

Now, 

Let the age of nuri is x years old 

and the age of sonu is y years 

we know that five years ago Nuri was thrice as old as sonu 

So, 

five years ago the age of Nuri = x - 5 years 

and five years ago the age of Sonu = y - 5 years 

then, 

according to the question - 

Age of nuri = 3* age of sonu 

Now putting the above values 

=> x - 5 = 3 × ( y - 5)

=> x - 5 = 3y - 15 

=> x - 3y = -10 .............................(1)

Now, 

After ten years the age of Nuri = x + 10 years 

And, after ten years the age of Sonu = y + 10 years 

according to the question 

The age of Nuri = 2* The age of sonu 

now, putting the above values 

=> x + 10 = 2×(y + 10)

=> x + 10 = 2y + 20

=> x - 2y = 10...........................(2)

Now, subtracting the equation 2 from equation 1 we get, 

x - 3y = -10

x - 2y = 10

----------------------
- y = -20

y = 20

now, we put it value of y in given equation 1 

=> x - 3 (20) = -10

=> x - 60 =- 10 

=> x = 50

Hence, the age of Nuri is 50 years 
and the age of sonu = 20 years