Question

Floor tiles are 25 cm squares. How many tiles
will be needed for a rectangular lawn 12 m long
and 10 m wide. Find the total cost at the rate
of Rs. 8 per tile.





(want clear image )​

Answer 1

Answer

$\large \boxed{\boxed{\mathsf{Total \: Cost = 3,84,000rs}}}$

Step-by-step Explanation :

Given :

• Area of square tiles are 25 cm squares.
• And length of rectangular lawn = 12m and
• Breadth = 10m
• Cost of one tile = ₹8

To find :

• How many tiles are required to fill the floor
• And Total cost of flooring the floor with tile

Solution :

Now according to question

Area of one Square tiles = 25cm sqr.

Now number of tiles required would be equal to =

$\longrightarrow \mathtt{No.\: tiles\: = \dfrac{Area \: Floor}{Area\: of\: One \: Square}}$

Now we know that

$\boxed{ \bigstar \: \mathtt{Area\: of\: Rectangle\: = Length \times Breadth}}$

Where here,

Length of floor = 12m

Breadth of floor = 10m (Breadth and width are same)

That is,

$\implies \mathsf{Area\: of\: Floor = 12m \times 10m}$

$\implies \mathsf{Area\: of\: Floor = 120m^2 = 1200000{cm}^{2} }$

Therefore we have,

$\longrightarrow \mathtt{No.\: tiles\: = \dfrac{Area \: Floor}{Area\: of\: One \: Square}}$

$\longrightarrow \mathtt{No.\: tiles\: = \dfrac{1200000{cm}^{2}}{25{cm}^{2}}}$

$\longrightarrow \mathtt{No.\: tiles\: = 48000}$

Therefore Total cost of Flooring

$\longrightarrow \mathtt{No. \: of \: Tiles \times Cost \: of \: one \: tile}$

That is ,

$\longrightarrow \mathsf{Total\: cost = (48000) \times (8)rs}$

$\longrightarrow \mathsf{Total\: cost = 3,84,000rs}$

Thus Required answer

$\underline{\boxed{\mathsf{Total \: Cost = 3,84,000rs}}}$