For a poission variate x, p(x=1) =p(x=2).Find p(x=5)
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Given a poisson variable satisfies P(X=1)=P(X=2)
The probability mass function of the poisson distribution can be defined as f(x)=
x!
e −λ λ x
where λ is a parameter.
Consider P(X=1)=P(X=2)
⇒ 1! e λ = ! e −λ λ
⇒1=
2
λ
⇒λ=2
Thus P(X=5)=
5!
e
−2
2
5
=0.0017
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