Question

For a reaction M2O(s) - 2M(s) + 1/2O2 (g); ΔH = 30 kJ mol-' & ΔS=0.07 kj K-mol
at 1 atm. The reaction would not be spontaneous at temperature​

Answer 1

Answer:

Hi

Here is your answer,

Given, ΔH = 400 k .mol ⁻¹ , ΔS = 0.2 kJ⁻¹

Gibbs free energy , ΔG = ΔH - TΔS

0 = 400 kJ mol⁻¹ - T × 0.2 kJ K⁻¹ mol⁻¹

Temperature, T = 400 kJ mol⁻¹/0.2 kJ K⁻¹ mol⁻¹

= 2000 K