For an A.P.if t4=12and d=-10 then find its tn
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given
t4=12
d=-10
t4=t+3d
12=t+3(-10)
12=t-30d
12+30=t
t=42
now
tn=t+(n-1)d
12=42+(n-1)(-10)
12-42=( n-1)(-10)
-30/-10=n-1
3+1=n
4=n
t4=12
d=-10
t4=t+3d
12=t+3(-10)
12=t-30d
12+30=t
t=42
now
tn=t+(n-1)d
12=42+(n-1)(-10)
12-42=( n-1)(-10)
-30/-10=n-1
3+1=n
4=n
shivam1073:
fool
so sorry my brother gived this answer
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