Question

for an acute angle A, if sec A = root 2, then sinA is equal to ________ ​

Answer 1

Answer:

1/root2

Step-by-step explanation:

sinA=root of secA^2-1/secA

sinA=root 2the whole square-1/root 2

sinA=2-1/root 2

SinA =1/root2

or

alternate method

according to the trigonometric table

sec 45°=root 2

then A= 45°

sin45°=1/root 2

Answer 2

Answer:

$\frac{1}{ \sqrt{2} }$