Physics, asked by topper1678, 8 months ago

For an anisotropic solid a values in x, y, z
direction is 2:3:7. If coefficient of
volume expansion is 2.4 x 10-6/°Cfind
areal expansion coefficient of the solid in
XZ plane.​

Answers

Answered by nirman95
1

Given:

For an anisotropic solid a values in x, y, z

direction is 2:3:7. Coefficient of

volume expansion is 2.4 x 10-6/°C.

To find:

Areal expansion coefficient of the solid in the XZ plane.

Calculation:

Let us assume "a" is the constant of proportionality.

So , the linear expansion coefficient along the respective axes will be :

  • X axis = 2a
  • Y axis = 3a
  • Z axis = 7a

We know that algebraic summation of the linear expansion coefficient along the three axes will give us the volume expansion coefficient.

2a + 3a + 7a = 2.4 \times  {10}^{ - 6}

 =  > 12a = 2.4 \times  {10}^{ - 6}

 =  > a = 2 \times  {10}^{ - 7}

So, Areal Expansion Coefficientcan be calculated by algebraic summation of the linear expansion coefficient along the X axis and the Z axis.

 \therefore \:  \beta _{XZ} = 2a + 7a

 =  >  \:  \beta _{XZ} = 9a

 =  >  \:  \beta _{XZ} = 9 \times (2 \times  {10}^{ - 7} )

 =  >  \:  \beta _{XZ} = 1.8 \times  {10}^{ - 6}  \:  \degree {C}^{ - 1}

So final answer is:

 \boxed{ \bold{\:  \beta _{XZ} = 1.8 \times  {10}^{ - 6}  \:  \degree {C}^{ - 1} }}

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