Question

for equation x square =3 roots are _____ ______​

Answer 1

Answer:

Consider the given equation.

x

3

−12x

2

+39x−28=0

Let the roots are a−d,a,a+d

So,

a−d+a+a+d=12

3a=12

a=4

And

(a−d)(a)(a+d)=28

a(a

2

−d

2

)=28

4(4

2

−d

2

)=28

(16−d

2

)=7

d

2

=9

d=±3

Hence, this is the answer.

Answer 2

Answer:

+root3 and -root3

Step-by-step explanation:

Now using the formula

D = b^2 - 4ac

b = 0 a = 1 and c = -3