Question

for finishing a job A need 2 days,B need 3 days and C need 6 days. how many days needed for the same job if they work together​

Answer 1

Answer: 1 day

Step-by-step explanation: Assume the total work to be 1 .

A needs 2 days to complete the work by himself .

∴ A can do 1/2 of the work in 1 day .

B needs 3 days to complete the work by himself .

∴ B can do 1/3 of the work in 1 day .

C needs 6 days to complete the work by himself .

∴ C can do 1/6 of the work in 1 day .

∴ Together A,B,C can do $\frac{1}{2} + \frac{1}{3} + \frac{1}{6}$ of the work in 1  day .

⇒ $\frac{1}{2} + \frac{1}{3} + \frac{1}{6}$

⇒ $\frac{3 + 2 + 1}{6}$  ⇒ $\frac{6}{6}$ = 1 , which means the whole work is completed .

∴ Together A,B,C can complete the work together in 1 day.