Question

For preparing 0.1M solution of H2SO4 in 1 litre.We need H2SO4

Answer 1

Answer: 9.8 g

Explanation: $Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is L}}$

given mass of compound $(H_2SO_4)$ = ?

Molar mass of $(H_2SO_4)$ = 98g/mol

Volume of solution= 1 L

$0.1M=\frac{\text{given mass of compound}}{98g/mol}\times 1L}}$

${\text{given mass of compound}}=9.8g$

Answer 2

We need 9.8 g/mol of sulphuric acid to make 0.1 M of 1 Litre sulphuric acid solution.

Molecular formula of sulphuric acid is ${ H }_{ 2 }{ SO }_{ 4 }$

$Molar\quad mass\quad of\quad { H }_{ 2 }{ SO }_{ 4 }\quad =\quad 2(1)\quad +\quad 32+\quad 4(16)$

$=\quad 2\quad +\quad 32\quad +\quad 64$

$Molar\quad mass\quad of\quad { H }_{ 2 }{ SO }_{ 4 }\quad =\quad 98\quad g/mol$

From the given molarity of ${ H }_{ 2 }{ SO }_{ 4 }$ is 0.1 M

$For\quad 1\quad mole\quad \rightarrow \quad 98\quad g/mol$

$For\quad 0.1\quad mole\quad =\quad 98\quad g/mol\quad \times \quad 0.1\quad =\quad 9.8\quad g/mol$