Question

for preparing Oxygen gas containing 600 atoms of oxygen the number of molecules of potassium of molecules of potassium chlorate required is

[ ]
1) 600
2) 300
3) 200
4) Cannot be predicted​

Answer 1

Answer:

Potassium chlorate is not required to prepare oxygen gas

Explanation:

Answer 2

The number of moles of potassium chlorate required to prepare oxygen gas containing 600 atoms of oxygen is equal to 200 moles.

• One mole of potassium chlorate dissociates to give one mole of KCl and 1.5 moles of oxygen gas.
• One mole of oxygen gas contains two atoms of oxygen, therefore 600 atoms of oxygen will be contained in 300 moles of oxygen gas.
• Since, 1.5 moles of oxygen gas is produced from one mole of potassium chlorate, 300 mole of oxygen gas will be produced from 200 (300/1.5) moles of potassium chlorate.