For the cross in part b, predict the frequencies of each of the phenotypes in the f1 progeny, and determine the genotype(s) present in each phenotypic class.
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The frequency obtained will be 1/2, 1/4 and 1/8.
- The frequencies of the four phenotypic groups are calculated by application of the rule of multiplication. For example, the green progeny accounts for 1⁄4 of the total progeny, since the likelihood of their formation depends on obtaining a y allele from both parents. ( Probability = 1/2 × 1/2 = 1/4)
- Likewise, the wrinkled offspring make up 1⁄2 of the total offspring, as the likelihood of their creation depends on both parents obtaining a r allele. ( Probability = 1 × 1/2 = 1/2).
- As the wrinkled, green progeny is both wrinkled and green at the same time, these events are independent, hence the multiplication rule is applied to get their frequency. ( Probability 1⁄4 x 1⁄2 = 1/8)
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