for the finite AP 40,35,30,.,-200, find the 10th term from the end.
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Given
a=40
d=35-40=-5
Let n be the number of terms
a+(n-1)d=-200
40-5n+5=-200
-5n=-245
=n=-245/-5
=n=49
10th term from the end is the 40th term .
a+39d
=40+39*-5
=40-195
=-155
Hope it helps.
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