for the given equation 2x+y=7. ,find value of y for x=0,1,2,3
Answers
Step-by-step explanation:
the given Linear equations, we can find any number of solutions by putting different values of x and obtain different values of y.
i) 2x + y = 7
Changing the subject of the equation to y, and solving, we get,
∴ y = 7 - 2x
Let us now take different values of x and substitute them in the given equation.
For x = 0, we get y = 7 - 2 (0) ⇒ y = 7. Hence, we get ( x, y ) = (0, 7)
For x = 1, we get y = 7 - 2 (1) ⇒ y = 5. Hence, we get ( x, y ) = (1, 5)
For x = 2, we get y = 7 - 2(2) ⇒ y = 3. Hence, we get ( x, y ) = (2, 3).
For x = 3, we get y = 7 - 2(3) ⇒ y = 1. Hence, we get ( x, y ) = (3, 1).
Therefore, four solutions of the given equation are (0, 7), (1, 5), (2, 3) and (3, 1).
ii) πx + y = 9
∴ y = 9 - πx
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 9 - π(0) ⇒ y = 9. Hence, we get ( x, y) = (0, 9)
For x = 1, y = 9 - π(1) ⇒ 9 - π. Hence, we get ( x, y) = (1, 9 - π)
For x = 2, y = 9 - π(2) ⇒ 9 - 2π. Hence, we get ( x, y) = (2, 9 - 2π)
For x = 3, y = 9 - π(3) ⇒ 9 - 3π. Hence, we get ( x, y) = (3, 9 - 3π)
Therefore, four solutions of the given equation are (0, 9), (1, 9 - π), ( 2, 9 - 2π) and (3, 9 - 3π).
iii) x = 4y
∴ y = x/4
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 0/4 = 0. Hence, we get (x, y) = (0, 0)
For x = 1, y = 1/4. Hence, we get (x, y) = (1, 1/4)
For x = 2, y = 2/4 = 1/2. Hence, we get (x, y) = (2, 1/2)
For x = 3, y = 3/4. Hence, we get (x, y) = (3, 3/4)
Therefore, four solutions of the given equation are (0, 0), (1, 1/4), (2, 1/2) and (3, 3/4).
Step-by-step explanation:
the given Linear equations, we can find any number of solutions by putting different values of x and obtain different values of y.
i) 2x + y = 7
Changing the subject of the equation to y, and solving, we get,
∴ y = 7 - 2x
Let us now take different values of x and substitute them in the given equation.
For x = 0, we get y = 7 - 2 (0) ⇒ y = 7. Hence, we get ( x, y ) = (0, 7)
For x = 1, we get y = 7 - 2 (1) ⇒ y = 5. Hence, we get ( x, y ) = (1, 5)
For x = 2, we get y = 7 - 2(2) ⇒ y = 3. Hence, we get ( x, y ) = (2, 3).
For x = 3, we get y = 7 - 2(3) ⇒ y = 1. Hence, we get ( x, y ) = (3, 1).
Therefore, four solutions of the given equation are (0, 7), (1, 5), (2, 3) and (3, 1).
ii) πx + y = 9
∴ y = 9 - πx
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 9 - π(0) ⇒ y = 9. Hence, we get ( x, y) = (0, 9)
For x = 1, y = 9 - π(1) ⇒ 9 - π. Hence, we get ( x, y) = (1, 9 - π)
For x = 2, y = 9 - π(2) ⇒ 9 - 2π. Hence, we get ( x, y) = (2, 9 - 2π)
For x = 3, y = 9 - π(3) ⇒ 9 - 3π. Hence, we get ( x, y) = (3, 9 - 3π)
Therefore, four solutions of the given equation are (0, 9), (1, 9 - π), ( 2, 9 - 2π) and (3, 9 - 3π).
iii) x = 4y
∴ y = x/4
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 0/4 = 0. Hence, we get (x, y) = (0, 0)
For x = 1, y = 1/4. Hence, we get (x, y) = (1, 1/4)
For x = 2, y = 2/4 = 1/2. Hence, we get (x, y) = (2, 1/2)
For x = 3, y = 3/4. Hence, we get (x, y) = (3, 3/4)
Therefore, four solutions of the given equation are (0, 0), (1, 1/4), (2, 1/2) and (3, 3/4).
Step-by-step explanation:
the given Linear equations, we can find any number of solutions by putting different values of x and obtain different values of y.
i) 2x + y = 7
Changing the subject of the equation to y, and solving, we get,
∴ y = 7 - 2x
Let us now take different values of x and substitute them in the given equation.
For x = 0, we get y = 7 - 2 (0) ⇒ y = 7. Hence, we get ( x, y ) = (0, 7)
For x = 1, we get y = 7 - 2 (1) ⇒ y = 5. Hence, we get ( x, y ) = (1, 5)
For x = 2, we get y = 7 - 2(2) ⇒ y = 3. Hence, we get ( x, y ) = (2, 3).
For x = 3, we get y = 7 - 2(3) ⇒ y = 1. Hence, we get ( x, y ) = (3, 1).
Therefore, four solutions of the given equation are (0, 7), (1, 5), (2, 3) and (3, 1).
ii) πx + y = 9
∴ y = 9 - πx
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 9 - π(0) ⇒ y = 9. Hence, we get ( x, y) = (0, 9)
For x = 1, y = 9 - π(1) ⇒ 9 - π. Hence, we get ( x, y) = (1, 9 - π)
For x = 2, y = 9 - π(2) ⇒ 9 - 2π. Hence, we get ( x, y) = (2, 9 - 2π)
For x = 3, y = 9 - π(3) ⇒ 9 - 3π. Hence, we get ( x, y) = (3, 9 - 3π)
Therefore, four solutions of the given equation are (0, 9), (1, 9 - π), ( 2, 9 - 2π) and (3, 9 - 3π).
iii) x = 4y
∴ y = x/4
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 0/4 = 0. Hence, we get (x, y) = (0, 0)
For x = 1, y = 1/4. Hence, we get (x, y) = (1, 1/4)
For x = 2, y = 2/4 = 1/2. Hence, we get (x, y) = (2, 1/2)
For x = 3, y = 3/4. Hence, we get (x, y) = (3, 3/4)
Therefore, four solutions of the given equation are (0, 0), (1, 1/4), (2, 1/2) and (3, 3/4).
Step-by-step explanation:
the given Linear equations, we can find any number of solutions by putting different values of x and obtain different values of y.
i) 2x + y = 7
Changing the subject of the equation to y, and solving, we get,
∴ y = 7 - 2x
Let us now take different values of x and substitute them in the given equation.
For x = 0, we get y = 7 - 2 (0) ⇒ y = 7. Hence, we get ( x, y ) = (0, 7)
For x = 1, we get y = 7 - 2 (1) ⇒ y = 5. Hence, we get ( x, y ) = (1, 5)
For x = 2, we get y = 7 - 2(2) ⇒ y = 3. Hence, we get ( x, y ) = (2, 3).
For x = 3, we get y = 7 - 2(3) ⇒ y = 1. Hence, we get ( x, y ) = (3, 1).
Therefore, four solutions of the given equation are (0, 7), (1, 5), (2, 3) and (3, 1).
ii) πx + y = 9
∴ y = 9 - πx
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 9 - π(0) ⇒ y = 9. Hence, we get ( x, y) = (0, 9)
For x = 1, y = 9 - π(1) ⇒ 9 - π. Hence, we get ( x, y) = (1, 9 - π)
For x = 2, y = 9 - π(2) ⇒ 9 - 2π. Hence, we get ( x, y) = (2, 9 - 2π)
For x = 3, y = 9 - π(3) ⇒ 9 - 3π. Hence, we get ( x, y) = (3, 9 - 3π)
Therefore, four solutions of the given equation are (0, 9), (1, 9 - π), ( 2, 9 - 2π) and (3, 9 - 3π).
iii) x = 4y
∴ y = x/4
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 0/4 = 0. Hence, we get (x, y) = (0, 0)
For x = 1, y = 1/4. Hence, we get (x, y) = (1, 1/4)
For x = 2, y = 2/4 = 1/2. Hence, we get (x, y) = (2, 1/2)
For x = 3, y = 3/4. Hence, we get (x, y) = (3, 3/4)
Therefore, four solutions of the given equation are (0, 0), (1, 1/4), (2, 1/2) and (3, 3/4).
Step-by-step explanation:
the given Linear equations, we can find any number of solutions by putting different values of x and obtain different values of y.
i) 2x + y = 7
Changing the subject of the equation to y, and solving, we get,
∴ y = 7 - 2x
Let us now take different values of x and substitute them in the given equation.
For x = 0, we get y = 7 - 2 (0) ⇒ y = 7. Hence, we get ( x, y ) = (0, 7)
For x = 1, we get y = 7 - 2 (1) ⇒ y = 5. Hence, we get ( x, y ) = (1, 5)
For x = 2, we get y = 7 - 2(2) ⇒ y = 3. Hence, we get ( x, y ) = (2, 3).
For x = 3, we get y = 7 - 2(3) ⇒ y = 1. Hence, we get ( x, y ) = (3, 1).
Therefore, four solutions of the given equation are (0, 7), (1, 5), (2, 3) and (3, 1).
ii) πx + y = 9
∴ y = 9 - πx
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 9 - π(0) ⇒ y = 9. Hence, we get ( x, y) = (0, 9)
For x = 1, y = 9 - π(1) ⇒ 9 - π. Hence, we get ( x, y) = (1, 9 - π)
For x = 2, y = 9 - π(2) ⇒ 9 - 2π. Hence, we get ( x, y) = (2, 9 - 2π)
For x = 3, y = 9 - π(3) ⇒ 9 - 3π. Hence, we get ( x, y) = (3, 9 - 3π)
Therefore, four solutions of the given equation are (0, 9), (1, 9 - π), ( 2, 9 - 2π) and (3, 9 - 3π).
iii) x = 4y
∴ y = x/4
Let us now take different values of x and substitute them in the given equation.
For x = 0, y = 0/4 = 0. Hence, we get (x, y) = (0, 0)
For x = 1, y = 1/4. Hence, we get (x, y) = (1, 1/4)
For x = 2, y = 2/4 = 1/2. Hence, we get (x, y) = (2, 1/2)
For x = 3, y = 3/4. Hence, we get (x, y) = (3, 3/4)
Therefore, four solutions of the given equation are (0, 0), (1, 1/4), (2, 1/2) and (3, 3/4).