Question

for the given progression 10,13,16,19,22.....find the 20th term

Answer 1

heya friend .⏩

here is ur answer. ...✋

first term."a"/t1=10

t2=13.

and as you know that common difference of an Ap =t2-t1

➡▶d"=13-10

d=3......

and tn=a+(n-1)d

so,. if you want to find t20 term .it will be...

t20=10+(20-1)3

=>10+57

=>67.....

from comment user are requesting to find t200 term..

so ,t200=10+(199)3

÷>t200=10+597

t200=607 Ans......

if you want sum of 200 term of an Ap.then..

sm=n/2(2a+(n-1)d

so,
=>s200=200/2【2*10 +(200-1)3

=>s200=100【20+597】

=>100*607

=>60700 =s200...



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hope it help you.....

@Rajukumar☺☺☺

Answer 2

An=a+(n-1)d
A20=10+(20-1)3
A20=67