Question

for the linear equation 3x-5y-15=0,find the point where its graph intersects x and y axis .

Answer 1

Answer:

The points of intersection of linear equation is (0 , - 3) and ( 5 , 0 )

Step-by-step explanation:

Given as :

The linear equation is express as

3 x - 5 y - 15 = 0

Or, 5 y = 3 x - 15

or y = $\dfrac{3}{5}$ x - $\dfrac{15}{5}$

Or, y = $\dfrac{3}{5}$ x - 3                       ......1

The equation is in the form of y = m x + c

where m is the slope of line

and c is the y-intercept

Now, point of intersection of line = (a , b)

Now, from eq 1

y = $\dfrac{3}{5}$ x - 3  

For  x = 0 ,  

y  = $\dfrac{3}{5}$ × 0 - 3  

Or, y = 0 - 3

∴ y = - 3

So, The point is ( 0 , - 3)

Again

For y = 0

i.e  0 =  $\dfrac{3}{5}$ x - 3

Or, 0 + 3 =  $\dfrac{3}{5}$ x

Or, 3 =  $\dfrac{3}{5}$ x

∴  x = $\dfrac{15}{3}$

i.e  x = 5

So, the another point is ( 5 , 0)

Hence, The points of intersection of linear equation is (0 , - 3) and ( 5 , 0 ) Answer

Answer 2

Answer:

(5,0) is a right answer thank you