Question

For the reaction 2A + B → A2B, rate = k [A] [B]2 with k = 20 x 10-6 mol-2 L2 s-1. Calculate the initial rate of the reaction when [A] = 0.1 mol L-1 and [B] = 0.2 mol L-1 Calculate the rate of reaction after [A] is reduced to 0.06 mol L-1.

Answer 1

Answer:

Explanation:

Given

       the rate of the reaction is

             rate = k [A][B]² .........{1}

and  k = 20×10^-6 mole^-2L^2s^-1

        [A] = 0.1 mol L^-1 and

        [B] = 0.2 mol L^-1

putting all the values in eq {1}

  rate = 20×10^-6 mol^-2L^2s^-1 ×0.1 mol L^-1×[0.2 mol L^-1]²

        = 20×10^-6 mol^-2L^2s^-1 ×0.1 mol L^-1× 0.04 mol^2 L^-2

       = 0.8 mol L^-1 s^-1

   Again

The rate of the reaction after [A] is reduced to 0.06 mol L^-1 is--

rate = 20×10^-6 mol^-2L^2s^-1 ×0.06 molL^-1×[0.2 mol L^-1]²

      =  20×10^-6 mol^-2L^2s^-1 ×0.06 molL^-1× 0.04 mol^2 L^-2

      =0.048 mol L^-1 s^-1