For the reaction 2Al+3H2SO4->Al2(SO4)3 + 3H2 how many grams of hydrogen are produced if 0.8 mole of aluminium reacts with 1.0 mole of sulphuric acid?
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Answer:
2Al + 3H2SO4---- Al2(SO4)3 + 3H2
No. of moles of Al: 0.8
No. of moles of H2SO4: 1
Applying Limiting reagent concept
0.8/2 > 1/3
Thus H2SO4 is LR
Thus ,
By stoichiometry,
No. of moles of H2SO4/3= no. of moles of H2/3
No. of moles of H2 = 1 moles
Thus weight = 1*2= 2 gram
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