Question

For the reaction n2(g)+3h2(g)‚áå2nh3(g) the rate of change of conentration for hydrogen is -0.3√ó10^-4 moles per second. the rate of change of concentration of ammonia is

Answer 1

The rate of change of concentration of ammonia is :

• Reaction n2(g)+3h2(g) => 2nh3(g)

=> -1/3{ d[Rh2] / dt }= -d[Rn2] / dt =1/2{ d[Rnh2] / dt }

• Given : 1/3{ d[Rh2] / dt } = -0.3×10^-4

• -1/3{ d[Rh2] / dt }= +1/2{ d[Rnh2] / dt }

• d[Rnh2]/dt = -2/3×{ d[Rh2] / dt }

= -2/3×(-0.3×10^-4)

= 0.2×10^-4

• Hence, rate of change of concentration of ammonia is 0.2×10^-4