Math, asked by pulakjyotidas3301, 1 year ago

If you won 1 mole of rupees in a lottery the day you were born and spent a billion repees every second . how much percentage dtill you will have the prize money the day when you will dieat the age of ninty years?

Answers

Answered by danielochich
108
One mole of a substance has the Avogadro's number of particles

The Avogadro's number = 6.022 x 10^23

So the amount you won = 6.022 x 10^23 rupees

One year = 365 days

90 years = 365 x 90 x 24 = 788400 hours

1 hour has 3600 seconds

788400 hours = 788400 x 3600 = 2838240000 seconds

You spend 1 billion per second

Amount spend = 2838240000 x 1,000, 000, 000

                        = 2.83824 x 10^18 rupees


Amount spend as a percentage = (2.83824 x 10^18)/(6.022 x 10^23) x 100

                                                   = 4.71 x 10^-5 %


The percentage remaining =  100 - 4.71x10^-5

                                           = 99.99995287 %
Answered by amitnrw
5

Given :  won  one mole of rupees in a lottery the day you were born and spent a billion rupees every second  

To Find :  how much percentage still you have  the prize money that day when you will die at age of 90 years

Solution:

1 mole = 6.022 * 10²³

1 hr =  3600 secs

1 year =  365 * 24 *   3600  = 3,15,36,000 secs

=> 90 years  = 2,83,82,40,000  secs

spent in 1 sec =  1 billion = 10⁹  Rs

Total Spent  = 2,83,82,40,000 *  10⁹   = 2.838 * 10¹⁸  

Left  %=  100  * ( 6.022 * 10²³ -   2.838 * 10¹⁸  ) / 6.022 * 10²³  = 99.9995 %

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