Question

For the reaction pcl3 + cl2 gives pcl5,the value of kc at 250 c is 26 dm^3.The value of kp at this temperature in atmosphere is

Answer 1

) 0.61Kp = Kc× (RT)^∆n∆n=(no of moles of gaseous products - no of moles of gaseous reactants)

Therefore, ∆n = 1-2= (-1)Now,

Kc=26, R=0.0821,

T= 250+273.15=523.15

Hence,

Kp= 26×(RT)^ -1

=26/RT =

26/(0.0821×523.15)

= 0.61

Answer 2

Answer:

0.61

Explanation:

Temperature=250c

Change into kelvin

250+273.15=523.15

Value of kc=26

there is a relation b/w the kb and kc

Kp=kc×(RT)∆n {∆n=product-reactant

1-2=-1}

=26×(0.0821×523.15)^–¹

=26/0.0821×523.15^+¹

=26/42.9884

=0.61

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