Question

For the reaction $A \rightarrow B$; $\Delta H$ = + 24 kJ/mol and $B \rightarrow C$; $\Delta H$ = – 18 kJ/mol, the decreasing order of enthalpy of A, B and C follows the order
(a) A, B, C
(b) B, C, A
(c) C, B, A
(d) C, A, B

Answer 1

(c) part is the correct option