Question

For the shown situation, if collision between blocks A and B is perfectly elastic, then find the maximum energy
stored in the spring in joules
​

Answer 1

Answer:4 jule

Explanation:At the time of maximum compression velocity of both blocks are same.

From linear momentum conservation,

           3*2 = (3+6)*v

             6 = 9v

              v= 2/3 m/$s^{2}$

From energy conservation,

              $\frac{1}{2}*3*2^{2}=\frac{1}{2}*(3+6)*(\frac{2}{3} ) ^{2}+ U$

                6= 2+U

                U= 4 Jule

Hence, maximum energy stored in the spring is 4 Jule

Answer 2

plz refer to the attachment

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