For what set of values x²+5x+6/x²+8x+15 is underfined
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Answer:
x^2
−5x+6=0=(x−2)(x−3)
Roots are 2 and 3
For x^2
−8x+15=0=(x−5)(x−3)
Roots are 3 and 5
We have common root =3
We know that common root is the root of x^2
+4x+q=0
Putting x=3 we get 9+12+q=0
⇒q=−21
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Answer:
6) For what set of values (1) - 3 - 5 (x ^ 2 + 5x + 6)/(x ^ 2 + 8x + 15) (2) - 5 is undefined? (3)-2,-3,-5 (4)-2,-3
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