Math, asked by princyAnbumozhi, 2 days ago

For what set of values x²+5x+6/x²+8x+15 is underfined​

Answers

Answered by spjog82
0

Answer:

x^2

−5x+6=0=(x−2)(x−3)

Roots are 2 and 3

For x^2

−8x+15=0=(x−5)(x−3)

Roots are 3 and 5

We have common root =3

We know that common root is the root of x^2

+4x+q=0

Putting x=3 we get 9+12+q=0

⇒q=−21

Answered by mohandasj
0

Answer:

6) For what set of values (1) - 3 - 5 (x ^ 2 + 5x + 6)/(x ^ 2 + 8x + 15) (2) - 5 is undefined? (3)-2,-3,-5 (4)-2,-3

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