For what the value of k are the roots of the quadratic equation 3x square + 2kx+27 = 0 real and equal
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As we know, for real equal roots we have
D = b2- 4ac = 0
here, b = 2k , a = 3 , c = 27
putting the values
= D = (2k)2- (4 x 3 x 27) = 0
= 0 = 4k2 - 324
= 4k2 = 324
= k2 = 324/4
= k2 = 81
= k = 9
therefore, for k = 9 the quadratic equation 3x2 + 2kx + 27 = 0 has real and equal roots.
D = b2- 4ac = 0
here, b = 2k , a = 3 , c = 27
putting the values
= D = (2k)2- (4 x 3 x 27) = 0
= 0 = 4k2 - 324
= 4k2 = 324
= k2 = 324/4
= k2 = 81
= k = 9
therefore, for k = 9 the quadratic equation 3x2 + 2kx + 27 = 0 has real and equal roots.
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