for what value of a are the vectors A =ai^-2j^+k^ and B =2ai^+aj^-4k^ perpendicular to each other?
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Given,
Vector A=ai^-2j^+k^,
vector B=2ai^+aj^-4k^
To Find,
Value of a.
Solution,
To prove perpendicular dot product of vector A and vector B should be zero.
So, A. B=0
⇒(ai^-2j^+k^) .(2ai^+aj^-4k^)=0
⇒2a²-2a-4=0
⇒a²-a-2=0
⇒a²-2a+a-2=0
⇒a(a-2)+1(a-2)=0
⇒(a-2)(a+1)=0
⇒a=2 or -1
Hence, value of a will be 2 or -1 so that two vectors will be perpendicular to each other.
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