Question

For what value of k, 4 is a zero of the polynomial x²-x-(2k + 2)?​

Answer 1

Answer: hi mate your answer is

Step-by-step explanation:

p(x) = x² - x - [ 2k + 2 ]

     

p(-4) =  [-4]² - [-4] - [ 2k + 2 ]

        = 16 + 4 - 2k - 2  = 0

        = 20 - 2k - 2 = 0

        18 - 2k = 0

18 = 2k

k = 18/2

k = 9

Answer 2

K = 5

Step-by-step explanation:

$P(x)=x^2-x-(2k+2)\\P(4)=(4)^2-4-(2k+2)\\P(4)=16-4-(2k+2)\\\Rightarrow16-4-2k-2\\\Rightarrow16-6-2k=0\\\Rightarrow10-2k=0\\\Rightarrow-2k=-10\\k=5$