for what value of k , in the polynomial p(x) =2x^2 - kx+3x + 19 exactly divived by x =2
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mhmohshin:
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Ello!!
Here's your answer
__________________________
Given , p ( x ) = 2 x^2 - kx + 3x + 19 = 0
Now , x = 2
p ( 2 ) = 2 × ( 2 )^2 - k × 2 + 3 × 2 + 19 = 0
=> 2 × 4 - 2k + 6 + 19 = 0
=> - 2k = - 19 - 6 - 8
=> - 2k = - ( 33 )
=> 2k = 33
=> k = 33 / 2
So , the value of k is 33 / 2
________________________
Hope it helps you dear!
★ Devil king
Here's your answer
__________________________
Given , p ( x ) = 2 x^2 - kx + 3x + 19 = 0
Now , x = 2
p ( 2 ) = 2 × ( 2 )^2 - k × 2 + 3 × 2 + 19 = 0
=> 2 × 4 - 2k + 6 + 19 = 0
=> - 2k = - 19 - 6 - 8
=> - 2k = - ( 33 )
=> 2k = 33
=> k = 33 / 2
So , the value of k is 33 / 2
________________________
Hope it helps you dear!
★ Devil king
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