Question

wavelength of high energy transition of H atom is 91.2 nm. calculate the corresponding wavelength of He+ ion

Answer 1

We know that ,

1/x = R*Z²*[1/(n1)²-1/(n2)²] where x is wavelength.

According to the question ,

1/91.2 = R*1²*[1/(n1)²-1/(n2)²]                        for hydrogen      ..................1

1/x = R*2²*[1/(n1)²-1/(n2)²]                            for helium           ..................2

Dividing the equations 1 and 2, we get,

x/91.2 = 1/4

x = 22.8 nm

Answer 2

Answer:

22.8nm

Explanation: