For what value of K ,is -1/2 a root of the equation 5x2 -7/2x +2K=0
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Answered by
3
5x^2-7/2x+2k=0
5(-1/2)-7/2 (-1/2)+2k=0
-5/2+7/2+2k=0
1+2k=0
2k=-1
k=-1/2
5(-1/2)-7/2 (-1/2)+2k=0
-5/2+7/2+2k=0
1+2k=0
2k=-1
k=-1/2
Answered by
1
since -1/2 is the root of eq
so, it satisfy it
the put x=-1/2 in the eq
then it becomes
5*1/4-7/2*(-1/2)+2k=0
5/4+7/4+2k=0
12/4+2k=0
3+2k=0
2k=-3
k=-3/2
so, it satisfy it
the put x=-1/2 in the eq
then it becomes
5*1/4-7/2*(-1/2)+2k=0
5/4+7/4+2k=0
12/4+2k=0
3+2k=0
2k=-3
k=-3/2
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