Math, asked by sreeharimp2003, 1 year ago

For what value of k the quadratic equation kx(x-2) =0 has real roots

Answers

Answered by mrnavaneedanfromtn

Answer:

Step-by-step explanation:

the given equation can be written in the form of

k {x}^{2} - 2kx + 6 = 0

now it has equal roots that means The Discriminant is 0

D = 0

Also

{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6

Hence the value of K is 6.

sreeharimp2003: Stupid answer

sreeharimp2003: I asked for kx(x-2)=0

priyankafruity17: i think there is a mistake in ur question

priyankafruity17: its should be kx(x-2)+6=0

priyankafruity17: then this answer given here will be correct

anamikasah330: Answer is k>=1

priyankafruity17: oh k

priyankafruity17: where did u get this wuestion frm?

priyankafruity17: question*

sreeharimp2003: K greater than zero is the ans

Answered by manitoshkumar123

Step-by-step explanation:

condition has real roots

D >0

kx(kx-2)=0

kx2 -2kx =0

ax2+bx+c=0

here, a=k, b= -2k, c=0

b2-4ac >0

4k2>0

k2=0/4

k2>0

k>0 .

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