Math, asked by rjyoti18082002, 1 year ago

Solve for'x'
1/a+b+x=1/a+1/b+1/x, where a≠0,b≠0, x≠0

Answers

Answered by hysharan
4

Answer:

Step-by-step explanation:

Attachments:
Answered by armaanarora880
3

Answer: PLZZ MARK AS BRAINLIEST

Step-by-step explanation:

1/a+b+x = 1/a + 1/b + 1/x

1/a+b+x - 1/x = 1/a + 1/b

x - a - b - x/a+b+x *x = b+a/ab

-a-b/ax + bx + x² = b+a/ab

-(a+b)/ax+ bx + x² = b+a/ab

a+b on LHS and Rhs cancels out...and then the equation becomes..

-1/ax + bx + x² = 1/ab

Cross multiplying ..

ax + bx + x² = -ab

x² + ax + bx + ab = 0

x(x + a) + b (x + a) = 0

(x+a)(x+b) = 0

x= -a , x= -b

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