Solve for'x'
1/a+b+x=1/a+1/b+1/x, where a≠0,b≠0, x≠0
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Step-by-step explanation:
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Answer: PLZZ MARK AS BRAINLIEST
Step-by-step explanation:
1/a+b+x = 1/a + 1/b + 1/x
1/a+b+x - 1/x = 1/a + 1/b
x - a - b - x/a+b+x *x = b+a/ab
-a-b/ax + bx + x² = b+a/ab
-(a+b)/ax+ bx + x² = b+a/ab
a+b on LHS and Rhs cancels out...and then the equation becomes..
-1/ax + bx + x² = 1/ab
Cross multiplying ..
ax + bx + x² = -ab
x² + ax + bx + ab = 0
x(x + a) + b (x + a) = 0
(x+a)(x+b) = 0
x= -a , x= -b
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