For what value of k the quadratic equation x2-kx+4=0 has distinct root ?
Answers
Answered by
1
HEY MATE...here's ur answer....
x^2-kx+4=0
ax^2+bx+c=0
a=1, b=(-k), c=4
D=b^2-4ac
=(-k)^2-4×1×4
=k^2-16
16=k^2
√16=k
k=4
x^2-kx+4=0
ax^2+bx+c=0
a=1, b=(-k), c=4
D=b^2-4ac
=(-k)^2-4×1×4
=k^2-16
16=k^2
√16=k
k=4
abhiyaduvanshji:
hyyy
Answered by
0
Hey you have your answer in the file below
Hope it helps you
Attachments:
Similar questions
Chemistry,
7 months ago
Chemistry,
7 months ago
Accountancy,
1 year ago
Math,
1 year ago
Physics,
1 year ago