for what value of k will be the following pair of linear equation have infinitely many solutions ? kx + 3y - (k - 3) = 0 ane 12x + ky - k = 0
Answers
Answered by
1
k/12=3/k=-(k-3)/-k
k²=36
k=√36=±6
k²=36
k=√36=±6
Answered by
1
to have infinitely many solutions A1/A2=B1/B2= C1/C2
.
.ie k/12=3/k
=>K²=36=>k=6
.
.
therefore k=6
.
.ie k/12=3/k
=>K²=36=>k=6
.
.
therefore k=6
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