Question

For what value of K will consecutive term of AP is 2k+1, 3k+3, 5k-1?

Answer 1

The common difference=( 3k+3) -( 2k+1) = (5k-1)-(3k+3)
or k+2= 2k-4
or k= 6

Answer 2

here a=2k+1
d= 3k+3-2k+1
= k+4
we know that 2b=a+c
2 (3k+3)=2k+1+(5k-1)
6k+6=2k+1+5k-1
6k+6=7k
6=7k-6k
6=k