Question

for what value of k will K + 9, 2 k - 1 and 2 k + 7 are the consecutive terms of an ap​

Answer 1

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here is ur answer....

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Answer 2

We know that in an A.P.

$t_{2} - t_{1} = t_{3} - t_{2}$

so,

2k-1-(k+9)=2k+7-(2k-1)

2k-1-k-9=2k+7-2k+1

k-10=8

k=10+8

k=18

Verification:

{2(18)-1}-{18+9}={2(18)+7}-{2(18)-1}

35-27=43-35

8=8

Therefore k=18

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