For what value of k will k+9, 2k+1, 2k+7are the consecutive term of AP.?
Ayushpratapsingh2210:
K = 14 hoga , 18 nahi , values put krke dekh ki AP mein h ya nahi , aur tune brainliest bhi mark kr diya
Bhai mujhe hint chahiye tha wo mil gya
Answers
Answered by
6
Hello....
Let us assume
k + 9 = a
2k - 1 = b
2k + 7 = c
In AP
a + c = 2b
(k + 9) + (2k + 7) = 2(2k - 1)
k + 9 + 2k + 7 = 4k - 2
3k + 16 = 4k - 2
3k - 4k = - 2 - 16
- k = - 18
k = 18
k = 18 terms k+9 , 2k - 1 , 2k + 7 are in AP
Let us assume
k + 9 = a
2k - 1 = b
2k + 7 = c
In AP
a + c = 2b
(k + 9) + (2k + 7) = 2(2k - 1)
k + 9 + 2k + 7 = 4k - 2
3k + 16 = 4k - 2
3k - 4k = - 2 - 16
- k = - 18
k = 18
k = 18 terms k+9 , 2k - 1 , 2k + 7 are in AP
Tq
wlcm
oh sorry
Its ok
But anshikha in question b= 2k+1
Brainliest mark krne se pehle chq kiya kr ki sahi se solved h bhi ya nhi , k = 14 hog
Ya i know
So how can u mark a wrong answer as brainliest :/
And i think thay u dont knw my method .
Answered by
3
For AP
2k + 1 = {(k+9)+(2k+7)} ÷ 2
2k + 1 = (3k + 16)/2
4k + 2 = 3k + 16
4k - 3k = 16 - 2
k = 14
The three terms are in AP for
k = 14
Mark as brainliest.
2k + 1 = {(k+9)+(2k+7)} ÷ 2
2k + 1 = (3k + 16)/2
4k + 2 = 3k + 16
4k - 3k = 16 - 2
k = 14
The three terms are in AP for
k = 14
Mark as brainliest.
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