For what value of K will the consecutive term 2K+1, 3k+3 and 5k-1 from an A. P
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Since the numbers are in AP , So,
3K+3-(2K+1) = 5K-1-(3K+3)
3K+3-2K-1 = 5K-1-3K-3
K+2 = 2K-4
K = 6.
So, the value of K is 6.
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3K+3-(2K+1) = 5K-1-(3K+3)
3K+3-2K-1 = 5K-1-3K-3
K+2 = 2K-4
K = 6.
So, the value of K is 6.
Hooe you will find it helpful....
Mark it as brainliest.
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