Question

for what value of k will the consecutive terms 2k+1,3k+3,and5k-1 for an A.P.

Answer 1

Hey Mate⭐⭐⭐

Here's ur answer ⤵⤵⤵

♦If 2k+1 , 3k+3 , 5k-1 are in A.P. then from the property of A.P. ,

➡3k+3-(2k+1)=5k-1-(3k+3)

➡3k+3-2k-1=5k-1-3k-3

➡k+2=2k-4

➡k=6

✔✔✔Hope it will help you ☺☺☺

Answer 2

Let a=2k+1

b = 3k+3

c =5k-1

Then

As,in A.P.

b-a =c-b

2 b= c+a

b =c+a/2

3k+3=5k-1+2k+2/2

2(3k+3)= 7k+1

6k+6=7k+1

7k-6k=6-1

K=5 answer

Hope it helps.