Question

For what value of m, is the polynomial x3

-2mx2

+16 divisible by (x+2)?​

Answer 1

Let p(x) = x^3-2mx^2+16 and g(x)=(x+2)

or,g(x)=0

or,x+2 =0

or, x= -2

p(-2)= (-2)^3-2m×(-2)^2+16

= -8-2m+4+16

=-8+20-2m

= 12-2m

2m=12

m=12/2

m= 6

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Answer 2

Answer:Let p(x) = x^3-2mx^2+16 and g(x)=(x+2)

or,g(x)=0

or,x+2 =0

or, x= -2

p(-2)= (-2)^3-2m×(-2)^2+16

= -8-2m+4+16

=-8+20-2m

= 12-2m

2m=12

m=12/2

m= 6

Step-by-step explanation: