Question

For what value of min 2x³+mx²+11x+m+3 is exactly divisible by 2x-1

Answer 1

Answer:  -43

Step-by-step explanation:

if given polynomial is divisible by 2x-1, then

2x-1 is a factor of 2x^3+mx^2+11x+3

therefore, putting x=1/2 in the given polynomial gives remainder zero

hence, 2(1/2)^3 + m(1/2)^2 + 11(1/2) + 3 =0

solving above eq. we get

2*(1/8) + m*(1/4) + (11/2) + 3 = 0

1/4 + m/4 + 22/4 + 12/4 = 0

1+m+22+12 = 0

m = -43

Answer 2

Answer:

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