For what value of n, are the nth terms of two APs: 63, 65, 67,… and 3, 10, 17,… equal? Solution: In the first AP a = 63 and d = 2 In the second AP a = 3 and d = 7 As per question, 63+2(n-1) = 2+ 7(n-1) Or, 61 = 5 (n-1) Or, n-1 = 61/5 As the result is not an integer so there wont be a term with equal values for both APs. CAN ANY ! EXPLAIN ME THIS??
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nth term of 1st series=63+2 (n-1)
nth term of 2nd series=3+7 (n-1)
now a/c 63+2n-2=3+7n-7
65=5n
n=13
nth term of 2nd series=3+7 (n-1)
now a/c 63+2n-2=3+7n-7
65=5n
n=13
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