Question

For what value of n, are the nth terms of two APs: 63, 65, 67,… and 3, 10, 17,… equal? Solution: In the first AP a = 63 and d = 2 In the second AP a = 3 and d = 7 As per question, 63+2(n-1) = 2+ 7(n-1) Or, 61 = 5 (n-1) Or, n-1 = 61/5 As the result is not an integer so there wont be a term with equal values for both APs. CAN ANY ! EXPLAIN ME THIS??

Answer 1

63 + 2(n-1) = 3 + 7(n-1)
5(n-1) = 60
n-1 = 12
n = 13

NB: You made a mistake by using 2 instead of 3 on the right hand side of your first equation. (a = 3 not 2)
Thanks