for what value of p are 2p+1,13,5p-3 three consecutive terms of ap?
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Answered by
8
Solution:
Given A.P : 2p+1 , 13 , 5p-3
Here ,
a1 = 2p + 1 ,
a2 = 13 ,
a3 = 5p - 3
We know that ,
a2 - a1 = a3 - a2
=> 13 - ( 2p + 1 ) = 5p - 3 - 13
=> 13 - 2p - 1 = 5p - 16
=> 12 - 2p = 5p - 16
=> 12 + 16 = 5p + 2p
=> 28 = 7p
=> 28/7 = p
=> 4 = p
=> p = 4
••••
Given A.P : 2p+1 , 13 , 5p-3
Here ,
a1 = 2p + 1 ,
a2 = 13 ,
a3 = 5p - 3
We know that ,
a2 - a1 = a3 - a2
=> 13 - ( 2p + 1 ) = 5p - 3 - 13
=> 13 - 2p - 1 = 5p - 16
=> 12 - 2p = 5p - 16
=> 12 + 16 = 5p + 2p
=> 28 = 7p
=> 28/7 = p
=> 4 = p
=> p = 4
••••
Answered by
13
hope this helps.........
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ravijha47:
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