Math, asked by ravijha47, 11 months ago

for what value of p are 2p+1,13,5p-3 three consecutive terms of ap?

Answers

Answered by mysticd
8
Solution:

Given A.P : 2p+1 , 13 , 5p-3

Here ,

a1 = 2p + 1 ,

a2 = 13 ,

a3 = 5p - 3

We know that ,

a2 - a1 = a3 - a2

=> 13 - ( 2p + 1 ) = 5p - 3 - 13

=> 13 - 2p - 1 = 5p - 16

=> 12 - 2p = 5p - 16

=> 12 + 16 = 5p + 2p

=> 28 = 7p

=> 28/7 = p

=> 4 = p

=> p = 4

••••
Answered by drashti5
13
hope this helps.........
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