Question

for what value of p will the following system of equations have no solution : (2p-1)x +(p-1)y =2p+1;y+3x-1 = 0

Answer 1

Given: Two equations (2p-1)x + (p-1)y = 2p + 1 and y + 3x - 1 = 0

To find: The value of p.

Solution:

• Now we have given two equations (2p-1)x + (p-1)y = 2p + 1 and 3x+y = 1

• and this system has no solution.

• So value of p will be:

• For no solution, the condition is:

                    a1/a2 = b1/b2 ≠ c1/c2

• So putting the values, we get:

                    2p-1/3 = p-1/1 ≠ 2p+1/1

                    2p-1/3 = p-1/1

                    2p-1 = 3(p-1)

                    2p-1 = 3p - 3

                    3-1 = 3p-2p

                    p = 2

Answer:

            So the value of p is 2.